Science · Lesson s03

Speed, Distance & Time

Die gleichförmige Bewegung — and why v = s/t is the slope you already know.


Schau dir das zuerst an — Lehrerschmidt erklärt das Formeldreieck für Geschwindigkeit, Weg und Zeit.

Lehrerschmidt — "Formeldreieck v = s/t | Physik – Mechanik" (~6 min)


🔎 Was fällt dir auf?

Mia's family drives from Valencia to Barcelona. She records the distance shown on the GPS at regular intervals:

Time elapsed (h)Distance from Valencia (km)
00
0.554
1.0108
1.5162
2.0216
2.5270
3.0324

Before reading on: What do you notice about the numbers in the right column? What is happening every 0.5 hours? Can you calculate the car's speed from this table?

💡 Deine Vermutung

If you plotted this data on a graph with time on the x-axis and distance on the y-axis, what would the graph look like? Sketch it quickly before reading further. What does the steepness of the line tell you?


📋 Die Grundformel: v = s / t

For an object moving at constant speed (gleichförmige Bewegung):

$$v = \frac{s}{t} \qquad s = v \cdot t \qquad t = \frac{s}{v}$$

Where: v = speed (Geschwindigkeit) · s = distance (Strecke/Weg) · t = time (Zeit)

[ s ]
[v] [t]

Cover the variable you want → what remains tells you how to calculate it.

Common units:

📈 Das Weg-Zeit-Diagramm (Distance-Time Graph)
🧪 Ausprobieren — Measure your own speed

You need: a phone timer, a tape measure or a known distance (e.g. 10 floor tiles).

  1. Measure out 10 metres (or estimate it using a known object).
  2. Walk the distance and time yourself. Record: distance = 10 m, time = ? s
  3. Calculate your walking speed in m/s using v = s ÷ t.
  4. Convert to km/h (multiply by 3.6). Is this a normal walking speed? (Typical: 1.2–1.6 m/s)
  5. Now run the same distance. How does your speed compare?

Worked Examples

Example 1 — Find the speed

Mia's train travels from Madrid to Málaga: 513 km in 2 hours 30 minutes. What is its average speed in km/h?

Convert time: 2 h 30 min = 2.5 hours
v = s ÷ t: 513 ÷ 2.5 = 205.2 km/h
This is the AVE high-speed train. At this speed the train covers about 57 m every second.
Example 2 — Two-segment journey

Mia cycles 12 km to a market at 15 km/h, then walks back 12 km at 5 km/h. What is her average speed for the whole trip?

Time cycling: t = s ÷ v = 12 ÷ 15 = 0.8 h
Time walking: t = 12 ÷ 5 = 2.4 h
Total distance: 12 + 12 = 24 km
Total time: 0.8 + 2.4 = 3.2 h
Average speed: 24 ÷ 3.2 = 7.5 km/h
⚠ Common mistake: (15 + 5) ÷ 2 = 10 km/h. This is wrong — you can't average speeds without accounting for the different times spent at each speed.

Problems

Science check ✔ — Average speed hides a lot. A car that drives 100 km in 1 hour might have stopped at traffic lights, driven at 130 km/h on the motorway, and crawled at 20 km/h through a town. The formula v = s/t gives the average over the whole journey — not what the speedometer showed at any single moment. In maths, instantaneous speed is the slope of a curve at a single point — which is the idea behind calculus.
Show Answer Key
1. 3 h · 420 km · 90 km/h · 146.25 km · 30 km/h 2. (a) 400 ÷ 6 ≈ 66.7 m/min · (b) 66.7 ÷ 60 ≈ 1.11 m/s · (c) 1.11 × 3.6 = 4 km/h 3. (a) slope = 300 ÷ 4 = 75 km/h · (b) the speed of the vehicle · (c) 75 × 7 = 525 km 4. Canter: 20 × (15/60) = 5 km · Gallop: 48 × (5/60) = 4 km · Total: 9 km = 9 000 m 5. t = 384 400 ÷ 299 792 ≈ 1.282 s → about 1.28 seconds (just over a second) 6. Relative speed = 18 − 4 = 14 km/h · t = 3.5 ÷ 14 = 0.25 h = 15 minutes 7. Into headwind: (p − w) × 4 = 2 400 → p − w = 600. With tailwind: (p + w) × 3 = 2 400 → p + w = 800. Adding: 2p = 1 400 → p = 700 km/h. Then w = 800 − 700 = 100 km/h. 8. Open — any correct calculation. Note: 20% faster speed gives 1/1.2 ≈ 83.3% of the original time, saving about 16.7% — not 20%. Speed and time are inversely related.
Next up → s04: Forces & Newton's Laws
What actually makes things speed up, slow down, or change direction? Newton figured out three rules that govern all motion — from horses to rockets.
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